Kean: Genius or Scoundrel
Originally released in 1957. Kean: Genius or Scoundrel is a comedy film. directed by Vittorio Gassman. At just 79 minutes, it's a tight, focused story.
Starring Vittorio Gassman, Eleonora Rossi Drago, and Nerio Bernardi
Synopsis
England, first half of the 19th century. Edmund Kean is a celebrated theatre actor, notorious for his tumultuous private life. He is in love with the beautiful countess Koefeld, wife of the Danish ambassador, to the consternation of his friend, the Prince of Wales. He is also hounded by Anna Damby, who wants to become an actress to escape a marriage to Lord Mewill.
Quick Facts
Release Date
March 4, 1957
68 years ago
Runtime
1h 19m
79 minutes total
User Rating
6.8/10
Good (4 votes)
Language
Italian
Original language
Country
Italy
Production
Director
Top Cast
Vittorio Gassman
as Edmund Kean
Eleonora Rossi Drago
as Countess Elena Koefeld
Nerio Bernardi
as Conte Koefeld
Mario Carotenuto
as Peter Patt
Carlo Mazzarella
as Dario
Gérard Landry
as Prince of Wales
Cesco Baseggio
as Salomon
Anna Maria Ferrero
as Anna Damby
Helmut Dantine
as Lord Mewl
Bianca Maria Fabbri
Production Details
- Status
- Released
- Original Language
- IT
Production Companies
- Lux Film
- Vides Cinematografica
Frequently Asked Questions
What is Kean: Genius or Scoundrel about?
England, first half of the 19th century. Edmund Kean is a celebrated theatre actor, notorious for his tumultuous private life. He is in love with the beautiful countess Koefeld, wife of the Danish ...
Who directed Kean: Genius or Scoundrel?
Kean: Genius or Scoundrel was directed by Vittorio Gassman.
How long is Kean: Genius or Scoundrel?
Kean: Genius or Scoundrel has a runtime of 1 hours and 19 minutes (79 minutes total).
When was Kean: Genius or Scoundrel released?
Kean: Genius or Scoundrel was released on March 4, 1957 in theaters.
Who are the main actors in Kean: Genius or Scoundrel?
The main cast of Kean: Genius or Scoundrel includes Vittorio Gassman, Eleonora Rossi Drago, Nerio Bernardi, Mario Carotenuto, Carlo Mazzarella.